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6a^2+7a-14=0
a = 6; b = 7; c = -14;
Δ = b2-4ac
Δ = 72-4·6·(-14)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{385}}{2*6}=\frac{-7-\sqrt{385}}{12} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{385}}{2*6}=\frac{-7+\sqrt{385}}{12} $
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